4.9x^2+30x-600=0

Solution for 4.9x^2+30x-600=0 equation:

4.9x^2+30x-600=0

a = 4.9; b = 30; c = -600;
Δ = b2-4ac
Δ = 302-4·4.9·(-600)
Δ = 12660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12660}=\sqrt{4*3165}=\sqrt{4}*\sqrt{3165}=2\sqrt{3165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{3165}}{2*4.9}=\frac{-30-2\sqrt{3165}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{3165}}{2*4.9}=\frac{-30+2\sqrt{3165}}{9.8}
$